Spray bar question

[Pescador]

I knew I had this somewhere when I figured out mine.

Use area of a circle formula A = Pi * r^2 to calculate the area of the spray bar holes. and then calculate the area of the pump outlet, or the smallest diameter pipe in the outlet plumbing.

Make sure the sum of the hole areas on the spraybar is greater than the pump outlet calculation.

So if my math is right

1" pipe is .785 sq"
1/4" hole is .04908 sq "

.785 / .04908 = 15.9942 or 16 holes

[danny zubot]

Cool, I was planning on about 20. I'm not looking to have high pressured water come out of the spray bar, but I don't want to inhibit the flow.

Thanks,

Danny

[danny zubot]

Wait a minute. The pipe is 1" ID

3.14 x .5 = 1.57
1.57 x 1.57 = 2.46" sq

3.14 x .125 = .39
.39 x .39 = .15" sq

2.46 / .15 = 16 holes

Works out to be the same.

[Keana]

Just the other day I was thinking how I would like to put a spary bar on my tank for the return.... This thread is just in time for me! Thanks to eveyone that asked/answered the question. I have learned a lot from being on this forum.

[Pescador]

Just the radius is squared and then times pi
.5 x .5 = .25 x 3.14 =.785
It's gotta be smaller than a square inch cause it's round.

Order of operations is exponents first.
Good thing I was doing math homework with my boy.