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  #11  
Old 06-14-2004, 10:26 PM
DOO-E DOO-E is offline
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I will just get somebody to bend it for me.
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  #12  
Old 06-14-2004, 10:59 PM
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Volume of a cylinder is area * height. A corner bowfront tank is just a quarter cylinder. Therefore

V = (pi * r^2 * h)/4.

There are 264 US gallons in a cubic metre.

Good luck.

Ed
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  #13  
Old 06-14-2004, 11:23 PM
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uuuuuuuhhhhhhh ill get my dad to look at the furmula lets just put it this way i am in math 24.
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  #14  
Old 06-14-2004, 11:26 PM
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Quote:
Originally Posted by DOO-E
uuuuuuuhhhhhhh ill get my dad to look at the furmula lets just put it this way i am in math 24.
It's simple really. Volume =(3.14 x radius squared x height) all divided by 4.

pi is approximated to 3.14 for this calc.
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  #15  
Old 06-14-2004, 11:29 PM
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TOO.. MUCH ...MATH Must NOT THINK TOO HARD Okay guys i will break it down so i dont think too hard and hurt myself thanks
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  #16  
Old 06-15-2004, 01:20 AM
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http://www.thekrib.com/TankHardware/size-chart.html

Give's some common dimensions relative to their gallon size.

http://www.aquatics-warehouse.co.uk/...UV_filter.html

Has a calculator... but it may be more of a challenge estimating your 'corner' unit capacity.[/quote]
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  #17  
Old 06-15-2004, 01:24 AM
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You're going to have someone bend it for you? And so you're also going to cut the bottom piece into the correct shape?
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  #18  
Old 06-15-2004, 02:43 AM
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No avoiding math on this one. Here's an example:

My tank is 24 inches (0.6meters) tall and is a 34 in (0.86m) from back to front which is the radius.

Volume = pi * radius ^2 / 4 = 3.14 * 0.86 * 0.86 / 4 = 0.348 m3

0.348 m3 * (264 gallons/ 1 m3) = 91.96 gallons. My tank is listed as 92 gallons- I guess I remembered something from high school!
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  #19  
Old 06-15-2004, 07:10 AM
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Hello,

Is it really true that it's a quarter cylinder? I have a feeling that not all bow fronts work that way. The best way to figure it out is to find out what is the radius (r) for the curve. Then find out the angle limits (theta1, theta2) within which the curve fits in. Then do the following:

Area = Integral from r'=0 to r'=r of Integral from theta'=theta1 to theta'=theta2 of r'*dtheta'*dr' - (r * cos[(theta2 - theta1)/2] * r * sin[(theta2 - theta1)/2])

Then to get volume, multiply Area by height of tank.

BTW, didn't double check this but I believe it is correct.

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  #20  
Old 06-15-2004, 01:19 PM
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OKay either i will build it and get all the glass pre cut or i will get it custom made not sure yet. If i do get it custom made i think i will get the stand and the hood custom made also.
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