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#1
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![]() I understand your thoughts on Ohm's Law and it seems right. The issue seems to be between the theory and what really happens when a string fails. Others who have done parallel builds have found that without the fuse, the amperages accross the remaining strings increase and either shorten the life of your LED's or destroy them. Could this be based upon how the first string failed? Maybe the worry is if the LED fails open?
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Mark... ![]() 290g Peninsula Display, 425g total volume. Setup Jan 2013. |
#2
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![]() <deleted post - may have contained inaccurate information - sorry!>
Last edited by abcha0s; 01-19-2011 at 06:29 PM. |
#3
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![]() I did a little more reading and perhaps my quick assessment of the behaviour of these circuits is in error. I figure that I better acknowledge my simple analysis before someone else points it out. As I said, I don't know anything about LEDs.
I'll do some more reading before posting again. Sorry if I derailed the thread. I think it's important to really understand what's going on here, but perhaps I'm not the guy to explain it. My explaination is accurate if a diode were simply a resistor, but of course they are not. The electrical charecteristics are different and that is what I need to better understand. - Sorry! |
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