Thread: resister/s needed to end up with the proper power levels.
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Old 01-09-2003, 04:19 AM
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I think its cerebral gas Steve. Lol

Yes I belive you are right. The voltage is dropped between the two resistances in series and the current remains the same.

My reasoning is somewhat different but close to the same answer

Total resistance = 18v/.02ma… = 900ohms
4.5v/18v = 25% therefore 900ohmsX 25%= 225 for the LED and 900-225= 675ohms for the drop down resistor
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